Question

(-50x^4y^2-25x^3y+15x^2)/14x
respuesta sii

Answer 1

Respuesta:

(

−

5

0

4

2

−

2

5

3

+

1

5

2

)

1

4

⋅

\frac{(-50x^{4}y^{2}-25x^{3}y+15x^{2})}{14} \cdot x

14(−50x4y2−25x3y+15x2)⋅x

Simplifica

1

(

−

5

0

4

2

−

2

5

3

+

1

5

2

1

4

)

⋅

(\frac{-50x^{4}y^{2}-25x^{3}y+15x^{2}}{14}) \cdot x

(14−50x4y2−25x3y+15x2)⋅x

(

−

5

0

4

2

−

2

5

3

+

1

5

2

)

⋅

1

4

\frac{(-50x^{4}y^{2}-25x^{3}y+15x^{2}) \cdot x}{14}

14(−50x4y2−25x3y+15x2)⋅x

2

(

−

5

0

4

2

−

2

5

3

+

1

5

2

)

⋅

1

4

\frac{{\color{#c92786}{(-50x^{4}y^{2}-25x^{3}y+15x^{2}) \cdot x}}}{14}

14(−50x4y2−25x3y+15x2)⋅x

−

5

0

5

2

−

2

5

4

+

1

5

3

1

4

\frac{{\color{#c92786}{-50x^{5}y^{2}-25yx^{4}+15x^{3}}}}{14}

14−50x5y2−25yx4+15x3

−

5

0

5

2

−

2

5

4

+

1

5

3

1

4