Question

$\sqrt[3]{x} + 3 = \sqrt{x - 1}$
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Answer 1

Respuesta:

Explicación paso a paso:

$\sqrt[3]{x}+3=\sqrt{x-1}$

$(\sqrt[3]{x}+3)^{2} =(\sqrt{x-1)^{2} }$

$\sqrt[3]{x} ^{2} +2(\sqrt[3]{x})(3)+3^{2} =x-1$

$\sqrt[3]{x} ^{2}+6\sqrt[3]{x} +9=x-1$

$\sqrt[3]{x} (\sqrt[3]{x}+6)=x-10$