Question

(x-5) =
(X+8)=
(a-1)=
(a+6)=

Answer 1

Respuesta:

(x-5)^2 = $x^{2} - 10x + 25$

(X+8)^2= $x^{2} + 16x + 64$

(a-1)^2= $a^{2} - a + 1$

(a+6)^2= $a^{2} + 12x + 36$