Question

El resultado de 8/9 + 7/8 + 3/6 es:
a)30/36
b)163/72
c)18/23
d)48/60

Al sumar 3/5 + 4/3 +2/9 obtenemos:
a)45/72
b)78/60
c)86/90
d)97/45

De la resta 23/15 - 34/40 se obtiene:
a)41/60
b)56/34
c)36/45
d)45/60

Al restar 20/60 - 24/120 obtenemos:
a)5/20
b)2/15
c)3/12
d)5/4

Al resolver ( 3/4 + 4/5 ) * 2/3 se obtiene:
a)30/45
b)27/36
c)31/30
d)23/24

(2/3 + 1/4 )* ( 8/3 - 2/9) equivale a:
a)72/56
b)121/54
c)36/48
d)63/84

Al resolver ( 2/5 + 3/4 ) dividido por ( 5/6 - 3/8 ) se obtiene:
a)3/15
b)138/55
c)7/12
d)11/5

(7/8 + 5/4 ) dividido por ( 2/6 - 3/24 ) es igual a.
a)11/24
b)13/20
c)51/5
d)34/9

Answer 1

Respuesta:

$\frac{8}{9} + \frac{7}{8} + \frac{3}{6} = \frac{64 + 63}{72} + \frac{1}{2} = \frac{127}{72} + \frac{1}{2} \\ \frac{254 + 72}{144} = \frac{326}{144} = \frac{163}{72}$

$\frac{3}{5} + \frac{4}{3} + \frac{2}{9} = \frac{9 + 20}{15} + \frac{2}{9} = \frac{261 + 30}{135} \\ = \frac{97}{45}$

$\frac{23}{15} - \frac{34}{40} = \frac{920 - 510}{600} = \frac{410}{600} = \frac{41}{60}$

$\frac{20}{60} - \frac{24}{120} = \frac{1}{3} - \frac{1}{5} = \frac{5 - 3}{15} = \frac{2}{15}$

$( \frac{3}{4} + \frac{4}{5} ) \times \frac{2}{3} = \frac{31}{20} \times \frac{2}{3} = \frac{31}{30}$

$( \frac{2}{3} + \frac{1}{4} )\times ( \frac{8}{3} - \frac{2}{9} ) = \frac{11}{12} \times \frac{66}{27} \\ = \frac{121}{54}$

$\frac{( \frac{2}{5} + \frac{3}{4})}{( \frac{5}{6} - \frac{3}{8}) } = \frac{ \frac{8 + 15}{20} }{ \frac{40 - 18}{48} } = \frac{ \frac{23}{20} }{ \frac{22}{48} } = \frac{276}{100} = \frac{138}{55}$

$\frac{( \frac{7}{8} + \frac{5}{4} )}{( \frac{2}{6} - \frac{3}{24})} = \frac{ \frac{17}{8} }{ \frac{5}{24} } = \frac{51}{5}$

Answer 2

Respuesta:

1) 8/9 + 7/8 + 3/6 = $\frac{64+63+36}{72}$ =  163 / 72

2) 3/5 + 4/3 +2/9 = $\frac{27+60+10}{45}$ = 97/45

3)23/15 - 34/40 = $\frac{184-102}{120}$ = 82/ 120 = 41 / 60

4) 20/60 - 24- 120 = $\frac{160-48}{240}$ = 208/240 = 26/30 = 13/15

5)  3/4 + 4/5 ) * 2/3 = $\frac{15+16}{20}$* 2/3 = 31/20*2/3 =31/30

6) (2/3 + 1/4 )* ( 8/3 - 2/9)= (9/12) * ( 22/9) =99/54