Question

calcula 6(x+1)-(y+x)=8x-(y+3)

Answer 1

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$6(x+1)-(y+x)=8x-(y+3)$

$6x+6-\left(y+x\right)=8x-\left(y+3\right)$

$6x+6-y-x=8x-\left(y+3\right)$

$5x+6-y=8x-\left(y+3\right)$

$5x+6-y=8x-y-3$

$-3x+6-y=-y-3$

$-3x-y=-y-9$

$-3x=-y-9+y$

$-3x=-9$

$x=\frac{-9}{-3}$

x=3