Question

ayuda!!!!!!!
$\frac{\\37^{x+4} +37^{x+3} +37^{x+2} +37^{x+1} +37^{x} }{37^{x-4} +37^{x-3} +37^{x-2} +37^{x-1} +37^{x} }$

Answer 1

Respuesta:

1

Explicación paso a paso:

 ≈           $\frac{37x^{x}( 37x^{4}+ 37x^{3}+37x^{2}+37x^{+1}+ 1)}{37x^{x-4} (1+37x^{1}+37x^{2} +37x^{3}+37x^{4}) }$

 ≈           $\frac{37^{x} }{37^{x} }$

≈           $1$