Question

Si: x + y = 5; xy = 2; x >y
Hallar:
T= x² + y² – 3xy​

Answer 1

Respuesta:

15

Explicación paso a paso:

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ {5}^{2} = {x}^{2} + {y}^{2} + 2 \times 2 \\ 25 = {x}^{2} + {y}^{2} + 4 \\ {x}^{2} + {y}^{2} = 21$

Para hallar T:

${x}^{2} + {y}^{2} - 3xy \\ 21 - 3 \times 2 \\ 21 - 6 \\ 15$