Question

: Metodo sostitucion
2(x- y) = 5 - 3y
2(3y - 1) = 3(x + y ) - 14​

Answer 1

Respuesta:

aquí lo hice todo junto

2(x- y) = 5 - 3y

2(3y - 1) = 3(x + y ) - 14​

$\begin{bmatrix}2\left(x-y\right)=5\\ -3y\cdot \:2\left(3y-1\right)=3\left(x+y\right)-14\end{bmatrix}\\\\\begin{pmatrix}x=\frac{5}{2}-\frac{\sqrt{13}}{6},\:&y=-\frac{\sqrt{13}}{6}\end{pmatrix}$

aquí separado porque no si si son 2 o es uno solo

1. 2(x- y) = 5 - 3y

$\frac{2\left(x-y\right)}{2}=\frac{5}{2}-\frac{3y}{2}\\\\x-y=\frac{5-3y}{2}\\\\-y+y=\frac{5-3y}{2}+y\\\\x=\frac{5-3y}{2}+y$

2. 2(3y - 1) = 3(x + y ) - 14​

$\left(x+y\right)-14=2\left(3y-1\right)\\\\3\left(x+y\right)-14+14=2\left(3y-1\right)+14\\\\3\left(x+y\right)=6y+12\\\\\frac{3\left(x+y\right)}{3}=\frac{6y}{3}+\frac{12}{3}\\\\x+y=2\left(y+2\right)\\\\x+y-y=2\left(y+2\right)-y\\\\x=y+4$