Question

Hallar (J ∪ I) ∩ H, si
H = {x/x ∈ IN, 3 ≤ x ≤ 8}
I = {x/x ∈ IN, x + 5 = 12}
J= {x/x ∈ IN, 3x + 4 = 22}

Answer 1

Respuesta:

Explicación paso a paso:

H = {x/x ∈ IN, 3 ≤ x ≤ 8} = { 3, 4, 5, 6, 7, 8}

I = {x/x ∈ IN, x + 5 = 12} = {7}

J= {x/x ∈ IN, 3x + 4 = 22} = {6}

J ∪ I = {6, 7}

(J ∪ I) ∩ H = {6, 7}