Question

hallar el conjunto solucion de las siguientes ecuaciones.
xfa es para mañana :(​

Answer 1

Explicación paso a paso:

$\sqrt{7x+9} = 11\\\sqrt{7x+9} - 11 = 0\\(\sqrt{7x+9} - 11)^{2} = 0^{2}\\(\sqrt{7x+9})^{2} - 2(\sqrt{7x+9})(11) + 11^{2} = 0\\7x+9 - 22(\sqrt{7x+9}) + 121 = 0\\7x + 130 = 22\sqrt{7x+9}\\(7x + 130)^{2} = (22\sqrt{7x+9})^{2}\\49x^{2} + 2(7x)(130) + 130^{2} = 22^{2} (7x+9)\\49x^{2} + 1 820x + 16 900 = 484(7x+9)\\49x^{2} + 1 820x + 16 900 = 3 388x + 4 356\\49x^{2} + 12 544 = 1568x\\x^{2} + 256 = 32x\\x^{2} - 32x + 256 = 0\\(x - 16)^{2} = 0\\x = 16$

$\frac{x^{3}-1}{5} = 43\\\\x^{3}-1 = 43(5)\\x^{3}-1 = 215\\x^{3} = 215 + 1\\x^{3} = 216\\x^{3} = 6^{3} \\x = 6$