Question

Masa de 6.7 Lts de O2​

Answer 1

Respuesta:

1. Mm O2 = 32 g/mol

Calcular moles (n = m/Mm)

1 mol ----- 22.4 L

x ----- 67.2 L

x = 3 mol

Calcular masa ( n= m/Mm)

masa = 3 mol x 32 g/mol

masa = 96 g de O2

2. Mm CO2 = 44 g/mol

Calcular moles ( n = m/Mm)

n = 5 g / 44 g/mol

n = 0.113 moles

Calcular volumen

1 mol ----- 22.4 L

0.113 mol ----- x

x = 2.53 L

3. Mm NH3 = 17 g/mol

Calcular moles ( n = m/Mm)

n = 20 g / 17 g/mol

n = 1.176 moles

calcular volumen

1 mol ----- 22.4 L

1.176 mol ----- x

x = 26.34 L