Question

Realiza las conversiones adecuadas para completar la siguiente tabla de escalas de temperatura utilizando las fórmulas de conversión.
(imagen)

Answer 1

-5 C a F

f= c ×1.8 +32

F= 1.8(-5) +32

F = 23

-5 C a K

k = c + 273.15

k= -5 + 273.15

k= 268.15

32F a C

C = ( f - 32) ÷ 1.8

-5 = ( 32-32) ÷ 1.8

= 0C.

0c a k

k = c + 273.15

k= 0 + 273.15

k= 273.15

300 k a C

c = k- 273.15

300 - 273.15

C = 26.85

300 k a F

F = 1.8 ( k - 273.15) + 32

F = 1.8 (300-263.15) +32

F= 80.33

10 C a F

F = C x 1.8 + 32

F = 10 (1.8) ÷32

F = 50

10 C a K

K= C + 273.15

k = 10+ 273.15

k= 283.15

315 k a C

C = k - 273.15

C = 315 - 273.15

C = 41.85

315 k a F

F = 1.8 (k - 273.15) +32

F = 1.8 (315- 273.15) +32

F = 107.33

45 F a C

C = (F-32)÷1.8

C= (45-32) ÷1.8

C= 7.2

45 F a K

K = 5/9 (45-32) + 273.15

K = 5/9 (45-32) + 273.15

k = 280.37

33 C a F

F = C × 1.8 +32

F = 33(1.8) +32

F= 91.4

33 C a K

K= C + 273.15

K= 306.6