Question

ayúdenme porfavor lo necesito para orita​

Answer 1

Respuesta:

La solución de cada una, es la siguiente:

b.1) 2x - 12 = 4

2x = 4 + 12

2x = 16

x = 16/2

x =8

b.2) 4x - 24 = 8

4x = 8 + 24

4x = 32

x = 32/4

x = 8

b.3) 8x - 48 = 16

8x = 16 + 48

8x = 64

x = 64/8

x = 8

c.1) 4x - 4 = 20

4x = 20 + 4

4x = 24

x = 24/4

x = 6

c.2) x - 1 = 5

x = 5 + 1

x = 6

c.3) 16x - 16 = 80

16x = 80 + 16

16x = 96

x = 96/16

x = 6

e.1) x - 1 = 8

x = 8 + 1

x = 9

e.2) 1 - x = - 8

1 + 8 = x

9 = x

e.3) 5 - 5x = - 40

5 + 40 = 5x

45 = 5x

9 = x