-(5a^3b^2-4a^2b^2-4a^2b)^2 = Ayuda!!

Respuestas

Respuesta dada por: daseguras
1
-(5a^3b^2-4a^2b^2-4a^2b)^2=

-
((5a^3b^2-4a^2b^2)-4a^2b)^2=

-(
(5a^3b^2-4a^2b^2)^2 -2(5a^3b^2-4a^2b^2)*4a^2b + (4a^2b)^2)=

-((
5a^3b^2)^2 -2(5a^3b^2)(4a^2b^2)+(4a^2b^2)^2  -2(20a^5b^3 -16a^4b^3) + 16a^4b^2) =

-(25a^6b^4 -40a^5b^4+16a^4b^4 -40a^5b^3 +32a^4b^3+16a^4b^2)=

-25a^6b^4 +40a^5b^4-16a^4b^4 +40a^5b^3 -32a^4b^3-16a^4b^2

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