Question

ayudenmeeeee

hay que calcular
${((1\2})^{ -1} + {6}^{ - 1} + {3}^{ - 1}) { }^{ - 2}$
porfavorrrrr​

Answer 1

Hola.

Propiedades de las potencias

$a^{-b}=(\frac{1}{a})^{b}$

$a^{1}=a$

Nos queda

$((\frac{1}{2})^{-1}+6^{-1}+3^{-1})^{-2}$

$(2^{1}+(\frac{1}{6})^{1} + (\frac{1}{3})^{1})^{-2}$

$(2+\frac{1}{6}+\frac{1}{3})^{-2}$            $(m.c.m.$ $6)$

$(\frac{12+1+2}{6})^{-2}$

$(\frac{15}{6})^{-2}$                      $(simplificando$  $\frac{15}{6}=\frac{5}{2})$

$(\frac{5}{2})^{-2}$

$(\frac{2}{5})^{2}$

$\frac{2^{2}}{5^{2}}=\frac{4}{25}$

R. Letra c)

Un cordial saludo.