Question

a)
12x(7+2)+(45-32 )+8 =
b)
(7x5)x2 + 4x 8-(7 8+15) =
c)
81:9+12-6+(7x9 ) +11 =​

Answer 1

Respuesta:

12x(7+2)+(45-32 )+8:108x+21

Vamos a simplificar paso a paso.

12x(7+2)+45−32+8

=108x+45+−32+8

Combinar términos comunes:

=108x+45+−32+8

=(108x)+(45+−32+8)

=108x+21

(7x5)x2 + 4x 8-(7 8+15) :

Vamos a simplificar paso a paso.

7x5x2+4x(8)−((7)(8)+15)=7x7+32x−71

Distribuir el signo negativo:

=7x5x2+4x(8)+−1((7)(8)+15)

=7x5x2+4x(8)+−1(7)(8)+(−1)(15)

=7x5x2+4x(8)+−56+−15

=7x7+32x+−56+−15

Combinar términos comunes:

=7x7+32x+−56+−15

=(7x7)+(32x)+(−56+−15)

=7x7+32x+−71

81:9+12-6+(7x9 ) +11

 

81 /9 +12−6+(7)(9)+11

=9+12−6+(7)(9)+11

=21−6+(7)(9)+11

=15+(7)(9)+11

=15+63+11

=78+11

=89