Question

-³√1728+²√256-72÷³√5832
Por favor​

Answer 1

⇩⇩

$\frac{-\sqrt[3]{1728} + \sqrt{256 -72} }{\sqrt[3]{5832} }$

restamos  256 -  72 = 184

$\frac{-\sqrt[3]{1728} + \sqrt{184} }{\sqrt[3]{5832} } \\\\\sqrt[3]{5832} = 18\\\\\frac{-\sqrt[3]{1728} + \sqrt{184} }{18}$

$\sqrt[3]{1728} = 12\\\\\\ = 2 \sqrt46} \\\\\\\\\frac{-12 + 2 \sqrt{46} } {18}$

factorizamos $-12 + 2 \sqrt{46} : 2 (-6 +\sqrt{46}$

$\frac{2 (-6 + \sqrt{46}) }{18}$

⇒Por lo tanto la respuesta es $\frac{-6 +\sqrt{46} }{9}$

Espero te sirva salu2¡¡