Question

Pasar la siguientes temperaturas

1 ) de c a k
.25 c
.56 c
.10 c
.16 c
.92c

2 )de F A C
98f
32f
43f
36f
64f

3 )de k a c
943k
698k
508k
732k

4)de c a f
36c
10c
53c
22c
38c

Ayudenmen por el amor de dios gracias

Answer 1

1 ) de c a k

K = ºC + 273

K = 25 + 273 = 298 K

K = 56 + 273 = 329 K

K = 10 + 273 = 283 K
K = 16 +273 = 289 K

K = 92 + 273 = 365 K

2 )de F A C

ºC = (ºF – 32) / 1.8
ºC = (98 – 32 ) 1.8 = 36.66 ºC
ºC = ( 32 – 32 ) / 1.8 = 0ºC
ºC = (43 – 32 ) / 1.8 = 6.11 ºC
ºC = ( 36 – 32 ) / 1.8 = 2.22 ºC
ºC = ( 64 - 32 ) / 1.8 = 17.77 ºC

3 )de k a c

ºC = K – 273

ºC = 943 – 273 = 670 ºC
ºC = 698-  273 = 425 ºC
ºC = 508 – 273 = 235 ºC ºC = 732 – 273 = 459

4)de c a f
ºF ( ºC x 1.8 ) + 32

ºF = (36 x 1.8 ) + 32 = 96.8 ºF
ºF = (10 x 1.8 ) + 32 = 50 ºF

ºF = (53 x 1.8 ) + 32 = 127.4 ºF

ºF = (22 x 1.8 ) + 32 = 71.6 ºF
ºF = (38 x 1.8 ) + 32 = 100.4 ºF