Question

X ala 2 + 16x - 17= 0

Answer 1

x²+16x-17=0
de la forma:
ax²+bx+c=0
Raíces de x:
x=(-(b)+√(b²-4ac))/2a  ⇒ x=(-(16)+√((16)²-4(1)(-17)))/2(1)=(-16+18)/2=1
x=(-(b)-√(b²-4ac))/2a  ⇒ x=(-(16)-√((16)²-4(1)(-17)))/2(1)=(-16-18)/2=-17

Factoriza así:
(x-1)(x+17)

Answer 2

$x^2 +16x -17 = 0 \\ \\ Aplicamos \ Bhaskara \\ \\ x _{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\qquad a= 1\quad b= 16\quad c=-17 \\ \\ x _{1\ y\ 2}= \dfrac{-16\pm \sqrt{16^2-4(1)(-17)} }{2(1)}\\ \\ x _{1\ y\ 2}= \dfrac{-16\pm \sqrt{256-(-68)} }{2} \\ \\ x _{1\ y\ 2}= \dfrac{-16\pm \sqrt{256+68} }{2} \\ \\ x _{1\ y\ 2}= \dfrac{-16\pm \sqrt{324} }{2} \\ \\ x _{1\ y\ 2}= \dfrac{-16\pm18 }{2} \\ \\ \\ x _{1}= \dfrac{-16+18 }{2}\qquad \qquad x _{2}= \dfrac{-16-18 }{2}$

$x _{1}= \dfrac{2 }{2}\qquad \qquad \qquad x _{2}= \dfrac{-34 }{2} \\ \\ \boxed{x_1=1}\qquad \qquad \qquad \boxed{x_2= -17}$


$\boxed{ \boxed{x^2 +16x -17 = (x-1)(x+17)} }$



Espero que te sirva, salu2!!!!