Question

resuelve las siguientes operaciones
(√14/√7) (1/2)³× (4) / 4×√2
(√(3/√5))² ∛27/6×√8

Answer 1

$( \dfrac{ \sqrt{14} }{ \sqrt{7}}) ( \dfrac{1}{2})^3 * \dfrac{4}{4 \sqrt{2} }= \\ \\ ( \sqrt{ \dfrac{14}{7}}) ( \dfrac{1}{8})* \dfrac{1}{ \sqrt{2} }= \\ \\ \sqrt{2}* ( \dfrac{1}{8})* \dfrac{1}{ \sqrt{2} }= \\ \\ \not\sqrt{\not2}* ( \dfrac{1}{8})* \dfrac{1}{\not \sqrt{\not2} }= \boxed{ \dfrac{1}{8}}$




$( \dfrac{ \sqrt{3} }{ \sqrt{5}}) ^2 * \dfrac{ \sqrt[3]{27} }{6 \sqrt{8} }= \\ \\ \dfrac{ 3 }{5} * \dfrac{ 3 }{6*2 \sqrt{2} }=\\ \\ \dfrac{ 3 }{5} *\dfrac{ 3 }{12 \sqrt{2} }= \\ \\ \dfrac{ 3 }{5} *\dfrac{ 1 }{4 \sqrt{2} }= \\ \\ \dfrac{3 }{20 \sqrt{2} }* \dfrac{ \sqrt{2}}{ \sqrt{2}} = \dfrac{3 \sqrt{2}}{40}= \boxed{ \dfrac{3}{40} \sqrt{2}}$

Espero que te sirva, salu2!!!!