Question

a)_3x-(-11-4)+2x=(6-4x)

b)_4x-[-3+(x+5-2)+6]=[-(2x+5-6)]

c)_7x-{6-[3x+7-2x)-4]}=14-{5-[6x+(x-8)]}

d)_(5x-3)+(7x-1+x)-(18+x)=-[3+(5-x)]

PD: con verificación porfavor

Answer 1

3x-(-11-4)+2x=(6-4x)
3x(-15) + 2x = 6 - 4x
-45x +2x = 6 - 4x
-43x = 6 - 4x 
- 6 = -4x + 43x 
- 6 = 39x
-6/39 = x
-2/13 = x

4x-[-3+(x+5-2)+6]=[-(2x+5-6)]
4x-[-3+(x+3)+6]=[-(2x-1)]
4x-[-3+x+3+6]=[-2x+1]
4x-[+x+6]= -2x+1
4x- x -6 = -2x+1
3x - 6 = 2x +1
3x -2x = 1-6
x = -5


7x-{6-[3x+7-2x)-4]}=14-{5-[6x+(x-8)]}
7x-{6-[x+7-4]}=14-{5-[6x+x-8]}
7x-{6-[x+3] } = 14-{5-[7x-8}
7x-{6-x-3 } = 14-{5-7x+8}
7x-{3-x} = 14-{13-7x}
7x-3+x = 14-13+7x
8x - 3 = 1 + 7x
8x-7x = 1+3
x = 4
 

(5x-3)+(7x-1+x-(18+x)=-[3+(5-x)]
5x-3+(8x-1-18-x)= - [3+5-x]
5x-3+8x-1-18-x = -3-5+x
12x-22 = -8 + x
12x-x = 22-8
11x = 14
x =14/11