Question

a(4ab + 4a2) – (6a2 – 8ab) b (–5n2 + 9n + 3) – (–2n2– 4n + 1)
ayudad por favor doy corona

Answer 1

a(4ab+4a2)−(6a2−8ab)(b)(−5n2+9n+3)−(−2n2−4n+1)

Distribuir el signo negativo:

=a(4ab+4a2)−(6a2−8ab)(b)(−5n2+9n+3)+−1(−2n2−4n+1)

=a(4ab+4a2)+30a2bn2−40ab2n2−54a2bn+72ab2n−18a2b+24ab2+−1(−2n2)+−1(−4n)+(−1)(1)

=a(4ab+4a2)+30a2bn2−40ab2n2−54a2bn+72ab2n−18a2b+24ab2+2n2+4n+−1

Distribute:

=(a)(4ab)+(a)(4a2)+30a2bn2+−40ab2n2+−54a2bn+72ab2n+−18a2b+24ab2+2n2+4n+−1

=4a2b+4a3+30a2bn2+−40ab2n2+−54a2bn+72ab2n+−18a2b+24ab2+2n2+4n+−1

Combinar términos comunes:

=4a2b+4a3+30a2bn2+−40ab2n2+−54a2bn+72ab2n+−18a2b+24ab2+2n2+4n+−1

=(30a2bn2)+(−40ab2n2)+(−54a2bn)+(72ab2n)+(4a3)+(4a2b+−18a2b)+(24ab2)+(2n2)+(4n)+(−1)

=30a2bn2+−40ab2n2+−54a2bn+72ab2n+4a3+−14a2b+24ab2+2n2+4n+−1

solución:

=30a2bn2−40ab2n2−54a2bn+72ab2n+4a3−14a2b+24ab2+2n2+4n−1