Question

Ayuda por favor ya no se que más hacer ​

Answer 1

Respuesta:

A)

(x+6)(x+3) $\geq$ (x+1)(x-1)

$x^{2} + 3x + 6x + 18 \geq x^{2} - x +x -1\\\\x^{2} +9x + 18 \geq x^{2} - 1\\\\x^{2} + 9x - x^{2} \geq -1 - 18\\\\9x \geq - 19\\\\x\geq \frac{-19}{9}\\\\x \geq -2.11$

[ -2.11 ; +∞ )

B)

(2x+1)(x+4) < (x+5)^2 + x^2

$2x^{2} + 8x + x + 4 < x^{2} + 2(x)(5) + 5^2 + x^{2} \\\\2x^{2} +9x + 4 < x^{2} + 10x + 25 + x^{2} \\\\2x^{2} + 9x - x^{2} - 10x -x^{2} < 25 - 4\\\\-x < 21\\x>-21$

(-21 ; +∞)

Explicación paso a paso: