Question

1. Calcule el pH de las siguientes soluciones: HCl 10 ^– 5 N, KOH 3 x 10^-6 N, HCl 3 x 10^-4 N y el pOH del NaOH 5 x 10^-3N porfa ayuda con esto se lo agradecere bastante.

Answer 1

HCl

pH = - log [H⁺]

pH = -log (10⁻⁵)

pH = -(-5) = 5

KOH = 3 x 10⁻⁶

pOH = -log [OH⁻]

pOH = - Log(3 x 10⁻⁶)

pOH = -(-5.52) = 5.52

pOH + pH = 14

pH = 14 - 5.52 = 8.48

HCl  3 x 10⁻⁴

 pH = - log [H⁺]

pH = -log ( 3 x 10⁻⁴)

pH = -(-3.52) = 3.52

NaOH = 5 X 10⁻³

pOH = - log [OH⁻]

pOH = -log (5 x 10⁻³)

pOH = -(-2.30) = 2.30

pH + pOH = 14

pH = 14 - 2.30 = 11.7