Question

podeis resolverme los ejer. 6,7,8,9 y 10?

Answer 1

6) 3x² - 15x - 18 = 0

x² - 5x - 6 = 0

(x-2)(x-3)=0

x=2; x= 3

7) (-2x+5)² = 1

|-2x + 5| = 1 

x = 2; x = 3

9) (x³ - 3x² + 3x - 1)(5x-10) / (x² - 2x + 1)(x² - 4)
= 5(x-1)³(x-2) / (x-1)²(x-2)(x+2)
=5(x-1)/(x+2)