Question

¿Que volumen ocuparan 15 moles de CO2 a 27 grados C y a 800 mmHg?

Answer 1

V = ?

n = 15 moles

T = 27 + 273 = 300 K

1 atm ----- 760 mmHg
   x      ----- 800 mmHg
x = 1.05 atm

R = 0.0821 /L atm/mol K)

P x V = n x R x T

V = n x R x T
      ````````````
          P

V = 15 moles x 0.0821 /L atm/mol K) x 300 K
       ```````````````````````````````````````````````````````
                       1.052 atm

V = 351.18 L