Question

me ayudas porfa.....​

Answer 1

Respuesta:

a 27 7 27  as 33 3 3 . x3−33 x 3 - 3 3. Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2) a 3 - b 3

b a2 – ab + b2. ... a3 ± b3 = (a [Same sign] b)(a2 [Opposite sign] ab [Always Positive] b2) ... Note: The quadratic portion of each cube formula does not factor, so don't ... x3 – 8 = x3 – 23.

Explicació 8 3) z3 − 64 4) m3 + 27 5) 1 − t3 6) 125 + w3 7) 8 − z3 8) ... of a monomial ()m 33 3 Apply the difference of two perfect cubes formula ( 3)( ) ... of Cubes: a3 + b3 = (a + b)(a2 – ab + b2) Factoring a Difference of Cubes: a3 ...

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