Question

(-7)³•(7)³=

(35)⁰=

(-2)⁰=

(-4)²=

3⁵•3²=

(-7)⁰• (-7)⁵=

2⁴•2¹•2²=

×⁴•×¹⁰=

5⁶÷5²=

[(-2)³]²=

(-2)¹²÷(-2)¹⁰=

[(-5)¹]³=


resuelve las siguientes potencias utilizando las propiedades:

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Answer 1

Respuesta:

$( - {7 }^{3} ) \times ( {7}^{3} ) = - {7}^{3 + 3} = - {7}^{6} \\ {(35)}^{0} = 1 \\ {( - 2)}^{0} = 1 \\ {( - 4)}^{2} = - 4 \times - 4 = 16 \\ {3}^{5} \times {3}^{2} = {3}^{5 + 2} = {3}^{7} \\ {( - 7)}^{0} \times {( - 7)}^{5} = 1 \times {( - 7)}^{5} = - {7}^{5} \\ {2}^{4} \times {2}^{1} \times {2}^{2} = {2}^{4 + 1 + 2} = {2}^{7} \\ {x}^{4} \times {x}^{10} = {x}^{4 + 10} = {x}^{14} \\ {5}^{6} \div {5}^{2} = {5}^{6 - 2} = {5}^{4} \\ {( {( - 2 )}^{3} )}^{2} = {( - 2)}^{2 \times 3} = {( - 2)}^{6} \\ {( - 2)}^{12} - \div {( - 2)}^{10} = {( - 2)}^{12 - 10} = { ( - 2)}^{2} = - 2 \times - 2 = 4 \\ { ({( - 5)}^{1}) }^{3} = {( - 5)}^{1 \times 3} = {( - 5)}^{3} = - 125$