Question

halle el peso de
4 moles de c2h6
7 moles de k2cr2o7
14.3 moles de h20
0.47 moles de hno3
154.6 moles de kmno4

Answer 1

1.  Mm C2H6 = 30 g/mol

n(mol) = masa / Mm

masa  = mol x Mm

  m = 4 moles x 30 g/mol

m = 120 g

2. Mm K2Cr2o7 = 294 g/mol

m = 7 moles x 294 g/mol

m = 2058 g

3.  Mm H2O = 18 g/mol

m = 14.3 moles x 18 g/mol

m = 257.4 g

4.  Mm HNO3  = 63 g/mol

m = 0.47 mles x 63 g/mol

m = 29.61 g

5.  Mm KMnO4 = 158 g/mol

m = 154.6 moles x 158 g/mol

m = 24.426,8 g