Question

1.) 3ab 2.) 7/12 c3p2m 3.) b2mn 4.) 5/6 Ab-1 Mc-2 y los valores a=1 b=2 c=3 m=1/2 n=1/3 p=1/4

Answer 1

1.) 3(1)(2)= 6
2.) 7/12 c3p2m = (7/12)(3)(3)(1/4)(2)(1/2)= 126/96=21/16
3.) (2)(2)(1/2)(1/3)= 4/6
4.) (5/6)(1)(2)-1(1/2)(3)-2= (5/3)-1(3/2)-2= (2/3)(-1/2)= -2/6=-1/3.

Answer 2

Respuesta:

1.) 3(1)(2)= 6

2.) 7/12 c3p2m = (7/12)(3)(3)(1/4)(2)(1/2)= 126/96=21/16

3.) (2)(2)(1/2)(1/3)= 4/6

4.) (5/6)(1)(2)-1(1/2)(3)-2= (5/3)-1(3/2)-2= (2/3)(-1/2)= -2/6=-1/3.