Question

(x-2)al cuadrado +x(x-3)=3(x+4)(x-3)-(x+2)(x-1)+2

Answer 1

$(x-2)^2 +x(x-3)=3(x+4)(x-3)-(x+2)(x-1)+2\\ x^2-4x+4+x^2-3x=3(x^2-3x+4x-12)-(x^2-x+2x-2)+2\\ 2x^2-7x+4=3x^2+3x-36-x^2-x+2+2\\ 2x^2-7x+4=2x^2+2x-32\\ 2x^2-7x-2x^2-2x=-32-4\\ -9x=-36\\x=\frac{-36}{-9}\\\\x=4$