Question

Realizar las tablas de valores y representar en el plano cartesiano las siguientes

funciones:

a) f(x)= 2x2 con x: -2, -1, 0, 1 y 2


b) f(x)= x2 + 2x con x: 0, 1 , 2 y3

Ayuda por favor ​

Answer 1

Explicación paso a paso:

a) f (x) = 2x^2

x = -2:

f (x) = 2 (-2)^2 = 2 (4) = 8 --->(-2, 8)

x = -1:

f (x) = 2 (-1)^2 = 2 (1) = 2 --->(-1, 2)

x = 0:

f (x) = 2 (0)^2 = 2 (0) = 0 --->(0, 0)

x = 1:

f (x) = 2 (1)^2 = 2 (1) = 2 --->(1, 2)

x = 2:

f (x) = 2 (2)^2 = 2 (4) = 8 --->(2, 8)

b) f (x) = x^2 + 2x

x = 0:

f (x) = (0)^2 + 2(0) = 0+ 0 = 0 --->(0, 0)

x = 1:

f (x) = (1)^2 + 2(1) = 1 + 2 = 3 --->(1, 3)

x = 2:

f (x) = (2)^2 + 2(2) = 4 + 4 = 8 --->(2, 8)

x = 3:

f (x) = (3)^2 + 2(3) = 9 + 6 = 15 --->(3, 15)