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v = 1 litro
760 torr -------- 1 atm
458 torr -------- x
x = 0.603 atm.
m = 2.96 g
P x V = n x R x T n (mol) se sustituye por la formula n = masa/Mm
P x V = m/Mm x R x T despejar Mm
Mm = m x R x T
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P x V
R= 0.082 (atm L / mol K)
Mm = (2.96 g) x (0.082 (atm L / mol K)) x 680 K)
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0.602 atm. x 1Litro
Mm = 274.16 g/mol
Fm = HgCl2
760 torr -------- 1 atm
458 torr -------- x
x = 0.603 atm.
m = 2.96 g
P x V = n x R x T n (mol) se sustituye por la formula n = masa/Mm
P x V = m/Mm x R x T despejar Mm
Mm = m x R x T
``````````````
P x V
R= 0.082 (atm L / mol K)
Mm = (2.96 g) x (0.082 (atm L / mol K)) x 680 K)
``````````````````````````````````````````````````````````
0.602 atm. x 1Litro
Mm = 274.16 g/mol
Fm = HgCl2
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