Question

ayuda es para hoy examen final para terminar el año


(-3a3 + 4b2 – 6) + (a3 - 5b2 + 10) =


(1/5 x^3-8y^2-6)-(y^2-5x^3+10)=


(12 a3b2) . (2a3b – 4ab2 + 5) =


(7/12 x^5-4).(2/3 x^3-1/4 x^6 )=


(-3/2 a^6 b^5-3/4 a^8 b^3 )÷ (-1/3 a^6 b^2 )=


(-2/7 x^3 y^2+3/4 x^4 y)÷(-28xy)=

5/8⋅6/5-1/2=


-7/5+3/4.2/5÷3/2=



2,75 – 5,21 . 0,4 =


– 8,25 + 5,45 ÷ 0,5 . 3,8 =

Answer 1

1 25

2 35

3 57

4 65

5 21

6 98

7 10

9 -22

10 14