Question

Escribe cm nros fraccionarios y resolver

Answer 1

$a)~~ \frac{45}{99} - \frac{7}{11} ( -\frac{1}{3} )+3[ \frac{1}{3}-(1+ \frac{1}{11} ) ]\\\\ \frac{5}{11}+\frac{7}{33}+3[\frac{1}{3}-\frac{11+1}{11}]\\\\\frac{15+7}{33}+3[\frac{11-3(12)}{33}]\\\\\frac{22}{33}+\frac{-25}{11}=\frac{22-75}{33}\\\\\frac{-53}{33}\\\\\\b)~~ \frac{8}{21} +( \frac{-5}{9}-\frac{5}{3}(\frac{2}{3}) )-\frac{2}{7}\\\\\frac{8}{21}+(\frac{-5}{9}-\frac{10}{9})-\frac{2}{7}\\\\\frac{8}{21}-\frac{15}{9}-\frac{2}{7}=\frac{8}{21}-\frac{5}{3}-\frac{2}{7}\\\\\frac{-33}{21}=\frac{-11}{7}$
$c) \frac{-1}{3}-\frac{4}{3}(\frac{-6}{5}):(\frac{-9}{5}+\frac{11}{9})\\\\ \frac{-1}{3}+\frac{8}{5}:(\frac{-81+55}{45})\\\\ \frac{-1}{3}+\frac{8}{5}:(\frac{-26}{45})=\frac{-1}{3}+\frac{8}{5}(\frac{-45}{26})\\\\ \frac{-1}{3}-\frac{36}{13}\\\\\frac{-13-108}{39}\\\\\frac{-121}{39}$