Question

TAREA:
Resolver los siguientes sistemas de ecuaciones

Answer 1

Método de igualación

x + 2y = 5

2x - 5y = 1

5 - 2y 1 + 5y

_____ = _____

1 2

2 (5 - 2y) = 1 + 5y

10 - 4y = 1 + 5y

-4y - 5y = 1 - 10

(-) -9y = -9

9y = 9

y = 9/9

y = 1

x + 2y = 5

x + 2 (1) = 5

x + 2 = 5

x = 5 - 2

x = 3

2x - 5y = 1

2x - 5 (1) = 1

2x - 5 = 1

2x = 1 + 5

2x = 6

x = 6/2

x = 3

R// x = 3; y = 1

Método de sustitución

2x - y = -1

3x - 4y = 6

x1 = -1 + y/2

3 (-1 + y/2) - 4y = 6

3 (-1 + y) = 2 (6 + 4y)

-3 + 3y = 12 + 8y

3y - 8y = 12 + 3

(-) -5y = 15

5y = -15

y = -15/5

y = -3

2x - y = -1

2x - (-3) = -1

2x + 3 = -1

2x = -1 - 3

2x = -4

x = -4/2

x = -2

3x - 4y = 6

3x - 4 (-3) = 6

3x + 12 = 6

3x = 6 - 12

3x = -6

x = -6/3

x = -2

R// x = -2; y = -3

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