Question

15 operaciones monomios.
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Answer 1

Respuesta:

2x^{2}y^{3}z+3x^{2}y^{3}z=(2+3)x^{2}y^{3}z=5x^{2}y^{3}z

4xy+3xy-5xy=2xy

4x-5x-3x+2x=-2x

2x^{2}y^{3}+3x^{2}y^{3}z no se pueden sumar.

5\cdot (2x^{2}y^{3}z)=102x^{2}y^{3}z

\cfrac{30x^{4}y^{3}}{6xy^{2}}=5x^{4-1}y^{3-2}=5x^{3}y

 4x^6+3x^6 = 7x^6

5y^3-2y^3 = 3y^3

2x^2y+5x^2y-3x^2y = 4x^2y  

6abc-7abc+4abc = 3abc

6x^3y^2-4x^3y+2x^2y^3 = \color{red} \bm{\times}

2\cdot (6x^3) = (2\cdot 6)x^3 = 12x^3

-4\cdot (5x^7) = (-4\cdot 5)x^7 = -20x^7

5\cdot (-3a^4b) = (5\cdot (-3))a^4b = -15a^4b

-7(-6x^9y^5)= (-7\cdot (-6))x^9y^5=42x^9y^5

6x^4 \cdot 7x^5= (6\cdot 7)x^{4+5} = 42x^9

4y \cdot 2y^3 = (4\cdot 2)y^{1+3} = 8 y^4

5x^2y^4\cdot (-8x^8y^2)=(5\cdot (-8))x^{2+8}y^{4+2} = -40x^{10}y^6

-3x^6y^4 \cdot (-4x^2z)= (-3\cdot (-4)) x^{6+2}y^4z= 12x^8y^4z

-3x^8\cdot 4x^5\cdot (-x^2) =-12x^{13}\cdot (-x^2)= 12x^{15}

Explicación paso a paso: