Question

5logx/2 + 2logx/3 = 3logx - log32/9​

Answer 1

Respuesta:

$x=\sqrt[18]{20639121408}$

Explicación paso a paso:

$5\log _{10}\left(\frac{x}{2}\right)+2\log _{10}\left(\frac{x}{3}\right)=3\log _{10}\left(x\right)-\frac{\log _{10}\left(32\right)}{9}$

$5\log _{10}\left(\frac{x}{2}\right)\cdot \:9+2\log _{10}\left(\frac{x}{3}\right)\cdot \:9=3\log _{10}\left(x\right)\cdot \:9-\frac{\log _{10}\left(32\right)}{9}\cdot \:9$

$\frac{x^{63}}{2^{40}\cdot \:387420489}=x^{27}$

$x=0,\:x=-\sqrt[18]{20639121408},\:x=\sqrt[18]{20639121408}$

$x=\sqrt[18]{20639121408}$

$Decimal: x= 3.74143...$

(Espero que te haya servido de ayuda)