• Asignatura: Matemáticas
  • Autor: estrellitauwu31
  • hace 4 años

AYUDA por favor me harían un gran favor, gracias​

Adjuntos:

Respuestas

Respuesta dada por: IvyChen
1

Respuesta:

a) \frac{2}{5}  +  \frac{2}{5}  \times  \frac{3}{6}  =  \frac{2}{5}  +  \frac{2}{5}  \times  \frac{1}{2}  =  \frac{2}{5}  +  \frac{1}{5}  =  \frac{3}{5}

b) \frac{16}{3}  \times  \frac{3}{7}  - 2 \times  \frac{3}{7}  \div  \frac{4}{7}  =  \frac{16}{3}  \times  \frac{3}{7}  - 2 \times  \frac{3}{7}  \times  \frac{7}{4}  =  \frac{16}{7}  -  \frac{3}{2}  =  \frac{32}{14}  -  \frac{21}{14}  =  \frac{11}{14}

c) \frac{7}{5}  -  \frac{3}{2}  \times  \frac{1}{25}  -  \frac{1}{5}  =  \frac{7}{5}  -  \frac{3}{50}  -  \frac{1}{5}  =  \frac{70}{50}  -  \frac{3}{50}  -  \frac{10}{5}  =  \frac{57}{50}

d) \frac{6}{3}  \div  \frac{2}{3}  +  \frac{5}{2}  \times  \frac{3}{2}  =  \frac{6}{3}  \times  \frac{3}{2}  +  \frac{5}{2}  \times  \frac{3}{2}  = 3 +  \frac{15}{4}  =  \frac{12}{4}  +  \frac{15}{4}  =  \frac{27}{4}

e) \frac{5}{2}  \div  \frac{3}{9}  -  \frac{4}{5}  \times  \frac{1}{6}  - 6 =  \frac{5}{2}  \times  \frac{9}{3}  -  \frac{4}{5}  \times  \frac{1}{6}  - 6 =  \frac{15}{2}  -  \frac{2}{15}  - 6 = \frac{225}{30}  -  \frac{4}{30}   -  \frac{180}{30}  =  \frac{41}{30}

f) \frac{5}{2}  \times ( \frac{2}{3} -  \frac{4}{5}   \times  \frac{1}{6} ) =  \frac{5}{2}  \times ( \frac{2}{3}  -  \frac{2}{15} ) =  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{2}{15} ) =  \frac{5}{2}  \times  \frac{8}{15}  =  \frac{4}{3}

g) \frac{1}{5}  \div ( \frac{11}{3} - 1 ) =  \frac{1}{5}  \div ( \frac{11}{3}  -  \frac{3}{3} ) =  \frac{1}{5}  \div  \frac{8}{3}  =  \frac{1}{5}  \times  \frac{3}{8}  =  \frac{3} {40}

h)(5 - 2 \times  \frac{1}{4} ) - ( \frac{5}{3}  +  \frac{1}{6} ) = (5 -  \frac{1}{2} ) - ( \frac{5}{3} +  \frac{1}{6}  ) = ( \frac{10}{2} -  \frac{1}{2}  ) - ( \frac{10}{6}  +  \frac{1}{6} ) =  \frac{9}{2}  -  \frac{11}{6}  =  \frac{54}{12}  -  \frac{22}{12}  =  \frac{32}{12}  =  \frac{8}{3}

i)( \frac{1}{2} +  \frac{5}{3}  ) + 2 \div ( \frac{5}{2} + 3 \times  \frac{2}{4}  ) = ( \frac{1}{2} +  \frac{5}{3}  ) + 2 \div ( \frac{5}{2} +  \frac{3}{2}  ) = ( \frac{1}{2}  +  \frac{5}{3} ) + 2 \div \frac{8}{2}  = ( \frac{3}{6} +  \frac{10}{6}  ) + 2 \times  \frac{2}{8}  =  \frac{13}{6}  +  \frac{1}{2}  =  \frac{13}{6}  +  \frac{3}{6}  =  \frac{16}{6}  =  \frac{8}{3}

j) \frac{4}{3}  - ( \frac{3}{2}  -  \frac{2}{3} \div  \frac{3}{5}  ) +  \frac{1}{3}  =  \frac{4}{3}  - ( \frac{3}{2} -  \frac{2}{3}   \times  \frac{5}{3} ) +  \frac{1}{3}  =  \frac{4}{3}  - ( \frac{3}{2} -  \frac{10}{9}  ) +  \frac{1}{3}  =  \frac{4}{3}  - ( \frac{27}{18}  -  \frac{20}{18} ) +  \frac{1}{3}  =  \frac{4}{3}  -  \frac{7}{18}  +  \frac{1}{3}  =  \frac{24}{18}  -  \frac{7}{18}  +  \frac{6}{18}  = \frac{23}{18}

k)(1 -  \frac{2}{5}  \times  \frac{3}{4} ) \div ( \frac{5}{3} +  \frac{1}{6}  ) = (1 -  \frac{3}{10} ) \div ( \frac{5}{3}  +  \frac{1}{6} ) = ( \frac{10}{10} -  \frac{3}{10}  ) \div ( \frac{10}{6}  +  \frac{1}{6} ) =  \frac{7}{10}  \div  \frac{11}{6}  =  \frac{7}{10}  \times  \frac{6}{11}  =  \frac{21}{55}

l)8 - 3 \times (5 - 3 \div  \frac{2}{3} ) = 8 - 3 \times (5 - 3 \times  \frac{3}{2} ) = 8 - 3 \times (5 -  \frac{9}{2} ) = 8 - 3 \times ( \frac{10}{2} -  \frac{9}{2}  ) = 8 - 3 \times  \frac{1}{2}  = 8 - \frac{3}{2}  =  \frac{16}{2}  -  \frac{3}{2}  =  \frac{13}{2}

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