Question

despejar v2^2 de Δk = 1/2mv1^2 + 1/2mv2^2

Answer 1

$dk = \frac{1}{2} {mv1}^{2} + \frac{1}{2} {mv2}^{2} \\ dk = \frac{m}{2} ( {v1}^{2} + {v2}^{2} ) \\ \frac{2dk}{m} = {v1}^{2} + {v2}^{2} \\ {v2}^{2} = \frac{2dk}{m} - {v1}^{2} \\ v2 = \sqrt{ \frac{2dk}{m} - {v1}^{2} }$