Question

Expresa el valor de E en cada caso sin que aparescan los logaritmos : logE=2-3logx+logy-5logz

Answer 1

$LogE=2-3Logx+Logy-5Logz\\LogE=Log10^2-Logx^3+Logy-Logz^5\\LogE=(Log100+Logy)-(Logx^3+Logz^5)\\LogE=Log(100y)-Log(x^{3}z^{5})\\LogE=Log(\frac{100y}{x^{3}z^{5}})\\\\E=10^{Log(\frac{100y}{x^{3}z^{5}})}\\\\E=(\frac{100y}{x^{3}z^{5}})^{Log10}\\\\E=\frac{100y}{x^{3}z^{5}}$