Question

hallen el area de un triangulo equilatero de 16 cm de lado

Answer 1

A=√3/4 l²
A=√3/4(16)²
A=√3/4(256)
A=64√3 cm²

Answer 2

$A = \frac{ \sqrt{3} L^{2} }{4}$

$A = \frac{ \sqrt{3} (16)^{2} }{4}$

$A = \frac{ \sqrt{3} (256) }{4}$

$A = 64 \sqrt{3}$