Question

(x-2)^2+x(x+3)=3(x+4)(x-3)-(x+2)(x-1)+2

Answer 1

(x-2)^2+x(x+3)=3(x+4)(x-3)-(x+2)(x-1)+2
x^2 -4x+4+x^2+3x=3(x^2+x-12)-(x^2+x-2)+2
2x^2-x+4=3x^2+3x-36-x^2-x+2+2
2x^2-x+4=2x^2+2x-32

2x^2-2x^2-x-2x+4+32=0
-3x+36=0
3x=36
x=36/3
x=12

Answer 2

Respuesta:

(x-2)^2+x(x+3)=3(x+4)(x-3)-(x+2)(x-1)+2

x^2 -4x+4+x^2+3x=3(x^2+x-12)-(x^2+x-2)+2

2x^2-x+4=3x^2+3x-36-x^2-x+2+2

2x^2-x+4=2x^2+2x-32

2x^2-2x^2-x-2x+4+32=0

-3x+36=0

3x=36

x=36/3

x=12

Explicación paso a paso: