Question

(3/5x²-4/5x+2/5)+(x-2/5x²+7/5)=
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Answer 1

Taller:

$\left(\frac{3}{5}x^2-\frac{4}{5}x+\frac{2}{5}\right)+\left(x-\frac{2}{5}x^2+\frac{7}{5}\right)$

Solucion:

$=\frac{3}{5}x^2-\frac{4}{5}x+\frac{2}{5}+x-\frac{2}{5}x^2+\frac{7}{5}$

$=\frac{3}{5}x^2-\frac{2}{5}x^2-\frac{4}{5}x+x+\frac{2}{5}+\frac{7}{5}$

$=\frac{3}{5}x^2-\frac{2}{5}x^2=\frac{1}{5}x^2$

$=\frac{1}{5}x^2-\frac{4}{5}x+x+\frac{2}{5}+\frac{7}{5}$

$-\frac{4}{5}x+x=\frac{1}{5}x^2$

$=\frac{1}{5}x^2+\frac{1}{5}x+\frac{2}{5}+\frac{7}{5}$

$=\frac{1}{5}x^2==\frac{x}{5}^2$

$\frac{x}{5}x=\frac{x}{5}$

$=\frac{x^2}{5}+\frac{x}{5}+\frac{2}{5}+\frac{7}{5}$

$=\frac{x^2+x+2+7}{5}$

$=\frac{x^2+x+9}{5}$

$Psicopatacolombiano2$