Question

Points P(3,0) & Q (- 3, 4) are on the line
axtby=6. Find the value of a and b​

Answer 1

Answer:

a = 2

b = 3

Explanation:

The point P(3,0) is in the line, so x = 3 and y = 0. Then

ax + by = 6

a(3) + b(0) = 6

3a + 0 = 6

3a = 6

a = 6/3

a = 2

The point Q(–3, 4) is in the line, so here x = –3 and y = 4. Then

ax + by = 6

2(–3) + b(4) = 6

–6 + 4b = 6

4b = 6 + 6

4b = 12

b = 12/4

b = 3

Answer 2

(-4)×(+11)=

cuánto es el resultado