Question

CSCa
--------------------- = COSa
COTa + TAN a

Answer 1

(1/Sena)/(1/tana +tana)=cosa
(1/Sena)/(1+tan²a)/taña=cosa
tana/(sena(1+tan²a))=cosa
tana/(sena(sec²a))=cosa
tana/(sena(1/cos²a))=cosa
tana.cos²a/Sena=cosa
(Sena/cosa).cos²a=cosa.Sena
Sena.cosa=cosa.Sena
cosa=cosa