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Respuesta:
1212
Explicación paso a paso:
121212![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. \leq \geq \neq \pi \alpha \beta x_{123} \frac{x}{y} \sqrt[n]{x} \sqrt{x} x^{2} \\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B2%26amp%3B3%5C%5C4%26amp%3B5%26amp%3B6%5C%5C7%26amp%3B8%26amp%3B9%5Cend%7Barray%7D%5Cright%5D++%5Clim_%7Bn+%5Cto+%5Cinfty%7D+a_n+%5Cint%5Climits%5Ea_b+%7Bx%7D+%5C%2C+dx+%5Cleft+%5C%7B+%7B%7By%3D2%7D+%5Catop+%7Bx%3D2%7D%7D+%5Cright.+%5Cleq+%5Cgeq+%5Cneq+%5Cpi+%5Calpha+%5Cbeta+x_%7B123%7D+%5Cfrac%7Bx%7D%7By%7D+%5Csqrt%5Bn%5D%7Bx%7D+%5Csqrt%7Bx%7D+x%5E%7B2%7D+%5C%5C "\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. \leq \geq \neq \pi \alpha \beta x_{123} \frac{x}{y} \sqrt[n]{x} \sqrt{x} x^{2} \\")
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