Question

[(2/7 ) √64/49 + 1]÷(1/5)

Answer 1

Respuesta:

Holis!!

$\frac{\frac{\left(\frac{2}{7}\right)\sqrt{6}\cdot \:4}{49+1}}{\frac{1}{5}}\\=\frac{\frac{\frac{2}{7}\sqrt{6}\cdot \:4}{49+1}}{\frac{1}{5}}\\=\frac{\frac{4\sqrt{6}\frac{2}{7}}{50}}{\frac{1}{5}}\\=\frac{\frac{2}{7}\sqrt{6}\cdot \:4\cdot \:5}{50\cdot \:1}\\=\frac{\frac{2}{7}\sqrt{6}\cdot \:4\cdot \:5}{50}\\=\frac{20\sqrt{6}\frac{2}{7}}{50}\\=\frac{\frac{40\sqrt{6}}{7}}{50}\\=\frac{40\sqrt{6}}{7\cdot \:50}\\=\frac{40\sqrt{6}}{350}\\=\frac{4\sqrt{6}}{35}$

Explicación paso a paso:

Espero y te sirva

:)