Question

6r-5t=-11 y 7t-8r=15 metodo de suma y resta o reduccion paso a paso
porfavor lo ncesito para hoy :,,(

Answer 1

Método de reducción

6r - 5t = -11 (×7) (Ec1)

-8r + 7t = 15 (×5) (Ec2)

42r - 35t = -77

-40r + 35t = 75

_____________

2r // = -2

r = -2/2

r = -1

6r - 5t = -11 (Ec1)

6 (-1) - 5t = -11

-6 - 5t = -11

-5t = -11 + 6

(-) -5t = -5

5t = 5

t = 5/5

t = 1

-8r + 7t = 15 (Ec2)

-8 (-1) + 7t = 15

8 + 7t = 15

7t = 15 - 8

7t = 7

t = 7/7

t = 1

R// t = 1; r = -1

Comprobación

6r - 5t = -11

6 (-1) - 5 (1) = -11

-6 - 5 = -11

-11 = -11

-8r + 7t = 15

-8 (-1) + 7 (1) = 15

8 + 7 = 15

15 = 15

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