Question

Hallar el M.C.D. de


a) (320 , 440, 880)


b) (42, 56, 70, 84)​

Answer 1

Respuesta:

$a)320 = {2}^{6} \times 5 \\ 440 = {2}^{3} \times5 \times 11 \\ 880 = {2}^{4} \times 5 \times 11 \\ M.C.D.（320,440,880） = {2}^{3} \times 5 = 8 \times 5 = 40$

$b)42 = 2 \times 3 \times 7 \\ 56 = {2}^{3} \times 7 \\ 70 = 2 \times 5 \times 7 \\ 84 = {2}^{2} \times 3 \times 7 \\ M.C.D.（42,56,70,84） = 2 \times 7 = 14$